Calculated Industries ConcreteCalc User Manual download pdf (Page 38)

Concrete Columns

You’re going to pour five columns,

each with a diameter of 3 feet 4-1/2

inches and a height of 11 feet 6 inches.

How many cubic yards of concrete are

needed for all five columns? If the con-

crete weighs 1.75 tons per cubic yard,

what is the total weight in tons? In

pounds? In kilograms?

Step/Keystrokes Display

1. Clear calculator:

[On/C] [On/C] 0.

Find Cross-sectional Area of Column

2. Enter diameter and find surface area:

3 [Feet] 4 [Inch] 3 FT 4- 1.2 IN

1 [/] 2 [Circ] [Circ] 8.946176 SQ FT

Find Volume

3. Multiply by height and convert to

cubic yards:

[x] 11 [Feet]

6 [Inch] [=] 102.881 CU FT

[Conv] [Yds] 3.810408 CU YD

4. Multiply by 5 columns and enter into

Memory:

[x] 5 [=] 19.05204 CU YD

[M+]

38 – ConcreteCalc™

1 2 ... 33 34 35 36 37 38 39 40 41 42 43 ... 63 64

Comments to this Manuals

No comments